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ively, 15.5 and 6.4 and they act at 48 deg. to each other. Use the law of cosines to calculate the magnitude of the sultant vector A + B.

2006-09-06 12:21:06 · 3 answers · asked by drdagher89 2 in Science & Mathematics Physics

3 answers

The Law of Cosines is C^2=A^2+B^2-2*A*B*cos(angle opposite side C).

Thus, C^2=15.5^2+6.4^2-2.*15.5*6.4*cos(48/180*pi) = 1.48e2
Magnitude of resultant vector = C = sqrt(1.48e2) = 12

2006-09-06 16:07:55 · answer #1 · answered by tarahloft 2 · 0 0

you ought to p.c. any direction you elect. Any vector with fee 0 and a few direction is basically the 0-vector. notwithstanding, the well-known decision could in all possibility be to assign it direction 0 ranges. The direction 0 ranges is the +x direction.

2016-12-18 06:06:40 · answer #2 · answered by snelling 4 · 0 0

Guessing youre in either Calculus or Physics, Well this is really easy stuff, SO READ YOUR BOOK

2006-09-06 12:28:20 · answer #3 · answered by sur2124 4 · 0 9

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