(2x-3)(3x+4)
2006-09-06 10:57:40 · 6 answers · asked by many men 1 in Science & Mathematics ➔ Mathematics
Foil method...
(2x-3)(3x+4)
2x(3x+4)-3(3x+4)
6x^2 +8x -9x-12
6x^2 -1x -12
2006-09-06 11:09:23 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Use FOIL, between each set multipy these terms
First 2 + Outside 2 + Inside 2 + Last 2
(2x)(3x) + (2x)(4) + (-3)(3x) + (-3)(4)
6x^2 + 8x - 9x -12
6x^2 - x - 12
2006-09-06 18:06:08 · answer #2 · answered by godmike 2 · 0⤊ 0⤋
well many men . you need to multiply all of them together , like that;
(2x-3)(3x+4) =
[ (2x * 3x ) + (2x * +4) + (-3*3x ) +( -3 * 4) ] =
6x^2 + 8x - 9x - 12 =
6x^2 -x -12
Its your answer.
if you want to solve it , so ;
(2x-3)(3x+4)= 0
it measn
(2x-3) =0 ; 2x = 3 ; x = 3/2 .
(3x+4)= 0 ; 3x +-4 ; x= -4/3
Good Luck.
2006-09-06 19:41:22 · answer #3 · answered by sweetie 5 · 0⤊ 0⤋
(2x-3)(3x+4)=(2x)(3x) +(2x)(4) +(-3)(3x) + (-3)(4)
= 6x^2+ 8x - 9x -12
=6x^2 - x -12
2006-09-06 18:05:11 · answer #4 · answered by Amar Soni 7 · 0⤊ 0⤋
6x^2 - x - 12
2006-09-06 18:05:57 · answer #5 · answered by Pedromdrp 2 · 0⤊ 0⤋
yep looks that way to me lol
2006-09-06 18:04:04 · answer #6 · answered by mike L 4 · 0⤊ 0⤋