completing the square?

Question

complete the square of this quadratic y=x^2-10x then state the vertex.

Answer 1

To complete the square, look at the term with the x. Divide it's coeficient (the number out front, 10 in this case) by 2 and square it: (10/2)^2 = 5^2 = 25 To finish, simply add and subtract the same number (which is in essence, adding 0) to get

y = x^2 - 10x + 25 - 25
y = (x - 5)^2 - 25

The vertex will be the opposite term inside the parentheses as the x and the term outside as the y. So hrere the vertex is (5, -25)

Answer 2

It is y = (x - 5)^2 =x^2 - 10x + 25 then the vertex is in x = 5. y= 0

Answer 3

to complete the square:
divide 10 by 2 and square the result
(10/2)^2 = 5^2 = 25
Add 25 to both sides of the equation

y + 25 = x^2 - 10x + 25

Factor the left side

y + 25 = (x-5)^2

Equation for a parabola that opens up/down is y-k = a(x-h)^2
where (h,k) is the vertex, so in this case
V(5, -25)

Answer 4

Go to Planet Math dot org and review the rules and formula for completing the square. Then just plug in the rules and you will have the answers.

Answer 5

y=x^2-10x
y = x^2 -2(5)x +25 -25
y = (x-5)^2 -25
Vertex is (5,-25)

Answer 6

I see school started today.