physics problem plz help?

Question

A car traveling at a speed of vo = 57 m/s stops smoothly (that is, its deceleration is constant) over a distance of d = 110 m.

a) After the car has gone 1/3 of the stopping distance, what is its speed?

v1/3 =_____m/s
b) If the car had been going 10 m/s but had stopped in the same d = 110 m distance, what would its acceleration have been?

a(vo = 10m/s) =______ m/s2

Answer 1

a) Stops smoothly? If 2/3 of stopping distance is left, 2/3 of speed is left.

b) Use V^2 = Vo^2 + 2*a*d where V = 110m and Vo = 0.

Answer 2

wow