can u show me the work.
2006-09-06 09:42:27 · 8 answers · asked by phlp_bj 4 in Education & Reference ➔ Homework Help
joe is 15. bijan is 10.
25-5 = 20
20/2 = 10
10+5 = 15 (joe)
25-15= 10 (bijan)
2006-09-06 09:48:56 · answer #1 · answered by *Ginelle* 3 · 0⤊ 0⤋
Call Bijan x. Joe is 5+x (since he is older than Bijan).
x+(5+x) = 25 (since their combined ages is 25)
add like terms to get: 2x+5 = 25
Subtract 5 from both sides to get: 2x = 20.
Divide by 2 on both sides to solve for x.
x = 10. Bijan is x; therefore, Bijan is 10. Joe is 15.
2006-09-06 09:48:58 · answer #2 · answered by mthtchr05 5 · 0⤊ 0⤋
Bijan is x years old.
Joe is x+5 years old.
Both of their ages = 25, so:
x+(x+5)=25
2x+5=25.
2x=20
x=10
Bijan is 10 and Joe is 15.
2006-09-06 09:46:02 · answer #3 · answered by Lea A 5 · 1⤊ 0⤋
Joe - Bijan = 5
Joe + Bijan = 25
j - b = 5
j = 5 + b
j + b = 25
(5 + b) + b = 25
5 + 2b = 25
2b = 20
b = 10
j = 15
Bijan = 10 yrs old
Joe = 15 yrs old
2006-09-06 09:46:11 · answer #4 · answered by Will 4 · 0⤊ 0⤋
10 + 15 = 25
10 + 5 = 15
2006-09-06 09:48:21 · answer #5 · answered by customcat2000 4 · 0⤊ 0⤋
10 & 15
2006-09-06 09:48:04 · answer #6 · answered by Shay 1 · 0⤊ 0⤋
x + (x+5) = 25
x is Joe, x+5 is Bijan
2x+5=25
2x=20
x=10
Joe = 10, Bijan = 15
2006-09-06 09:45:45 · answer #7 · answered by dapixelator 6 · 1⤊ 1⤋
Joe is 15 and Bijan is 10....
2006-09-06 09:48:11 · answer #8 · answered by sem3578 2 · 0⤊ 0⤋