2006-09-06 09:17:18 · 5 answers · asked by webelieve04 2 in Science & Mathematics ➔ Mathematics
line..u hav the points right?..there's this equation..
y-y1= m(x-x1) where x1 and y1 are the coordinates of the point on the line.. s'pose it's 3, 8 and the slope=1
y-8= -1(x-3)
y-8= -x+3
y= -x+11
therefore
y=mx+b
got your equation?
2006-09-06 09:25:48 · answer #1 · answered by eatdungumbridge 3 · 0⤊ 0⤋
Let the line is passing through the point P on the y-Axis The distance from the origin to this point P will be equal to b. Then make an equation in y =mx +b
2006-09-06 16:30:15 · answer #2 · answered by Amar Soni 7 · 0⤊ 0⤋
b= the y intercept which means wherever the line crosses the y-axis
m= is the slope => count up and hten across and that it will give you your slope
then just plug into the equation
2006-09-06 16:24:51 · answer #3 · answered by naids56 2 · 0⤊ 0⤋
you put the slope where the "m" is. leave the "y" and "x" blank. then where the "b" is you put the y intercept. the y intercept is where the line crosses the y-axis if x=0.
2006-09-06 16:26:05 · answer #4 · answered by soccerwks1 1 · 0⤊ 0⤋
m = slope & b = y-intercept (the point the line hits the y-axis...(0,b))
2006-09-06 16:19:54 · answer #5 · answered by godmike 2 · 0⤊ 0⤋