Find the zeros of the polynomial function and state the multiplicity of each. try to work it out =)
1. f(x) = (x^2 - 9)^3 =
2. f(x) = -8(x-3)^2(x+4)^3x^4 =
2006-09-06 08:25:27 · 5 answers · asked by Austin's gf 1 in Education & Reference ➔ Homework Help
^^^^^Curly, just answer the dang question, i'd use a graphing calculator., its easy as pie
2006-09-08 05:59:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I am not doing your homework for you. Thats unethical.
The key ideas you need to understand are: what are zeros, how are they found, what is multiplicity of zeros, and how is it measured?
A zero is a value of x for which the function f(x) evaluates to zero.
If f(x) = x^2 -1 then when x equals plus or minus one the function evaluates to a zero.
Multiplicity is the measure of duplicate, or repeated zeros of a polynomial.
If f(x)=( x^2 -1) ^2 then f(x) equals zero when x equals plus or minus one, but there are two terms for each plus one and each minus one. Thats the multiplicity.
2006-09-06 18:16:29 · answer #2 · answered by Curly 6 · 0⤊ 0⤋
Use a graphing calculator to solve for the zeros of the functions. It will allow you to do that.
2006-09-06 15:30:56 · answer #3 · answered by mthtchr05 5 · 0⤊ 0⤋
1. -3 or 3
2. 0, 3, or -4
because when x = those numbers the answer is 0
2006-09-06 15:35:28 · answer #4 · answered by KLJ 1 · 0⤊ 0⤋
f(f2) =+b +c = d
2006-09-06 15:27:37 · answer #5 · answered by d_elmasry@sbcglobal.net 2 · 0⤊ 0⤋