plz help!!!?

Question

help plz!111?
write the increasing order of bond angle.....

H2O,ClO2,F2O,..........could u please tell me the procedure of solving this???/

Answer 1

the larger the 2 side items are, the wider the angle between them. the H2O has two hydrogens that are only 102.5 degrees apart, it has the narrowest bond angle. next would be the ClO2, and the widest would be F2O

Answer 2

bellerophon has the right order as far as I know, though F2O is better written as OF2, since F is the more electronegative element.

There are two "procedures", with links below. The first is based on fundamental forces, and the second is a theory using comparisons of known molecules to very similar molecules and is less precise. I don't think - and I apologize if my guess is wrong - that either one is something you want to tackle in an early course on chemistry.

What then? Search on "of2 bond angle" or "h2o bond angle" etc., and the first few hits in each search (Google search, anyway) give good data.

Hope this helps... I can tell you that even professional chemists would almost certainly search for published data rather than try to calculate values on their own.

Just needed to jump in here to point out that hanumaster couldn't be more wrong. He says the bigger angle arises between the bigger atoms, then shows the opposite, since H2O has the smallest atoms possible, but has a bigger bond angle than two of the others. Cl2O's two chlorines are much larger than ClO2's two oxygens, but their angle size order is the other way. On top of that the bond angle for water is 105 deg, not 102.5, and the angles for methane, ammonia, water are 109.5, 107, 105 despite the pendant groups' all being hydrogen. Go answer some political questions, hanumaster, where knowledge is not a key issue.

Answer 3

F2O
Though you can't really compare ClO2 with the others just like that.

F2O, Cl2O and H2O are all similar from the point of view that a single oxygen atom forms two single bonds with other atoms.
In all of these cases the molecule is a tetrahedral with oxygen in the center, 2 of its electron lone pairs on the two corners and the other atoms on the other two corners.

The angle is determined by the repulsion between the different electron pairs (electron pairs repell each other and try to be located as far away as possible from each other).

The strength of repulsion decreases in the manner;
lone pair-lone pair > lone pair-bond pair > bond pair-bond pair

The bond angle of X-O-X where X=F, Cl, H will be determined by the repulsion of the lone pairs and the bonding pairs. The more lone pair -bond pair repulsion increases the more the bonding angle increases.

The degree of this type of repulsion depends on the electronegativity of X. Hydrogen is the least electronegative. Thus the bonding pair of the O-H bond will be closer to O, resulting in a higher electron density near O at the site of the bond. This increases the repulsion with the lone pairs in the outer shell of oxygen and thus increases the bond angle.

For F it is the opposite; F is very electronegative and thus the electron density of the O-F bond near O is less than thatin O-H.
Thus the repulsion with the lone pairs of O is lower and the 2 lone pairs of O squeeze the two bonding pairs closer together so that the lone pairs themselves can be further away from each other.

ClO2 is not directly comparable and it is a special case
Had do do some search on it... The Cl-O bond is between a single and a double bond (and closer to a double bond; single for Cl-O would be 1.65 A for double 1.48 A and it is 1.53 +/-0.03 )http://www.pubmedcentral.nih.gov/articlerender.fcgi?artid=1086203
So the bonding pair is pretty similar to a lone pair, repulsions are maximized and so is the angle.

Answer 4

Sorry,