2006-09-06 03:54:48 · 8 answers · asked by Cory M 1 in Travel ➔ United States ➔ Las Vegas
Good apartments in Vegas cost over $1,000 per month. The only way to get one for that price is to find a total dump of a studio apartment that gets robbed all the time, or find two room mates and split the cost of a $1,500 apartment.
2006-09-06 06:11:05 · answer #1 · answered by ZCT 7 · 0⤊ 0⤋
Yea, try downtown. You're most likely to live next to hookers and junkies. A nice apartment will run between $750-1150 depending on how many rooms. I used to live in black mountain and was paying $850 for a 2 bath 2 bedroom place.
2006-09-07 01:07:33 · answer #2 · answered by Anna 3 · 0⤊ 0⤋
Coral Garden not the Ritz but safe & nice location next to Sams Town. $600 for Jr 1 bed room. $500 long gone.
2006-09-08 06:15:40 · answer #3 · answered by vegas_iwish 5 · 0⤊ 0⤋
You won't find much of anything worthwhile for that price. You might get a studio near UNLV, or some other scary area, but that's it.
The cheaper end of the nice places I've found is around $850 or so.
2006-09-07 03:48:09 · answer #4 · answered by zippythejessi 7 · 0⤊ 0⤋
No, I live in a safe, but very blue collar, ethnically mixed neighborhood and I pay $700 (and that's only because I've been there six years and I'm "grandfathered" in on my lease). $500 will get you a roach motel in a very bad area.
Most nicer apartments are in the $900+ range now.
2006-09-06 08:47:00 · answer #5 · answered by mistress_piper 5 · 1⤊ 1⤋
There is one place right here in phoenix for $500.00 per month. I guess you didnt want that though - according to your questions here in the last 3 months. It figure's...good luck
2006-09-10 02:39:04 · answer #6 · answered by David G 1 · 0⤊ 0⤋
www.ebay.com they have apt listings. I think its called www.rent.com
They will give you $100.00 if you find a apt thru them on that website. Have printer ready, to print confirmation.
2006-09-07 03:21:16 · answer #7 · answered by Anonymous · 0⤊ 0⤋
No such thing. Remember - you said "good".
2006-09-09 01:17:51 · answer #8 · answered by John K 3 · 0⤊ 0⤋