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2006-09-06 03:13:27 · 6 answers · asked by goring 6 in Science & Mathematics Physics

would it not bethe same equivalent as the electic field which is measured as an inverse meter squARE= meter^-2?

2006-09-06 03:40:11 · update #1

correction E field is in terms of inverse meter not meter^-2.

2006-09-06 03:49:07 · update #2

6 answers

There appears to be two possible answers to what you seek. The first is hf = c(g), Plank's constant times frequency is equal to the constant graviton. This may be converted to h = c(g) if all gravitons are the value of "h". That is the unknown.

Then, secondly, there is the value of "c" itself. If propagated gravitons have a velocity either a little less, or a little greater, than this, they could not wholly exist in our universe, because they would not equal the value of "c". http://360.yahoo.com/noddarc there is a short writing that compares magnetism with that of gravity "Magnetism - Gravity" that should answer your question.

2006-09-06 06:12:09 · answer #1 · answered by Anonymous · 0 0

The strength of the field at a specific location is measured in meters per square second, which is the same as newtons per kilogram, as the force acting on an object is proportinal to its mass.

2006-09-06 10:33:58 · answer #2 · answered by helene_thygesen 4 · 0 0

Gravitational constant

In 1774, G was determined by measuring the deflection of the vertical by the attraction of a mountain. This method is much inferior to the laboratory method in which the gravitational force between known masses is measured. In the torsion balance two small spheres, each of mass m, are connected by a light rod, suspended in the middle by a thin wire. The deflection caused by bringing two large spheres each of mass M near the small ones on opposite sides of the rod is measured, and the force is evaluated by observing the period of oscillation of the rod under the influence of the torsion of the wire (see illustration). This is known as the Cavendish experiment, in honor of H. Cavendish, who achieved the first reliable results by this method in 1797–1798. More recent determinations using various refinements yield the results: constant of gravitation G = 6.67 × 10?11 SI (mks) units; mass of Earth = 5.98 × 1024 kg. The result of the best available laboratory measurements, announced in 2002, is G = (6.6742 ± 0.0010) × 10?11 in SI (mks) units.

2006-09-06 10:34:01 · answer #3 · answered by Anonymous · 0 0

Strength of the field? The field is felt as a force. Forces are measure in Newtons. Remember, F=mA, force = mass * Acceleration. So a Newton (unit for force) = kg (unit for mass) * m/s^2 (unit for acceleration).

Answer is a Newton, or kg*m/s^2.

2006-09-06 10:24:49 · answer #4 · answered by Edward T 2 · 0 1

similar to acceleration = meters per second squared

2006-09-06 10:16:25 · answer #5 · answered by Know-it-all 4 · 1 0

same as the unit of acc

2006-09-06 12:25:46 · answer #6 · answered by jon k 1 · 0 0

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