Hey alok.. this has nothing to do with the earth's rotating speed.. Because Gravitational force, g = G M1M2 / r^2
G = 6.67 x 10^-11
M1 = Mass of object 1
M2 = Mass of object 2
r = distance between the centers of the two masses
the earth's mass is very huge.. and the mass of the apple is very very small. The apple experiences a force (the weight of the apple).. we actually see it and it's quite large.
Your weight is actually the product of your mass and the gravitational field strength of the earth.
That's equal to your mass x 9.81. (if your mass is 100kg, it's about 981N)
But why don't we feel the gravitational pull of the apple on us? this is because both the mass of the human and the apple are very small. It's probably 0.000000XX Newtons. Therefore we don't feel the apple's gravitational pull.
2006-09-06 02:09:04
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answer #1
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answered by Wonderous 2
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According to Newton's 3rd law, the earth also experiences an equal and opposite force to that acting on a falling object, an apple in this instance. The earth also accelerates towards the object, but because its mass is very huge compared to the falling apple, the acceleration is negligible.
2006-09-06 02:12:21
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answer #2
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answered by by the window 1
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An apple DOES exert a tiny gravitational attraction on the Earth. It is a very tiny attraction and is easily swamped by the vastly more powerful gravity of the Earth.
Any object with mass (which is all objects) exerts a gravitational force on the objects around it. It's just that the gravitational force from an apple, person or even a building is so small as to blown away by the force exerted by the Earth.
2006-09-06 01:48:43
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answer #3
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answered by pvreditor 7
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sorry but the earth does feel the gravity of an apple.
when you separate an apple and the earth and let go they drop towards each other, but the distance traveled by each is related to their masses, so the earth moves very little, and the apple a lot.
2006-09-06 01:46:37
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answer #4
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answered by Anonymous
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nicely, needless to say, if the stress from each and each group have been equivalent, *neither* could win. it could bring about a draw. to be certain that one group to win, the "internet" stress (on the rope a minimum of) won't be able to be 0. One group might desire to have extra stress than the different to avert a draw! yet how is this possible, decrease than Newton's 0.33 regulation!? The complicated section is that on a similar time as forces do, certainly are available in equivalent, opposing pairs, Newton does not specify precisely "who's pushing who." it fairly is not constantly clean the place those pairs ensue! to appreciate this extra suited, permit's say that rather of communities, 2 racecars are pulling on the ends of the rope. What happens as quickly as we unexpectedly decrease the rope with a great pair of scissors? each and each racecar is then pulling against.........what? Pulling against *not something*, are they? fairly, what's considerable right it rather is that the autos' tires are pushing against the *Earth*, and the Earth pushes back in an equivalent and opposite way. This explains why the autos could quickly improve up down the line as quickly as the rope is decrease. To be extra particular, the 0.33 regulation is a fact of "Conservation of Momentum," not conservation of stress. the main appropriate wording is "for each action there is an equivalent and opposite....." not "for each stress." A results of it rather is that the entire of each and every of the forces in a equipment might desire to 0, however the entire of many of the forces does not inevitably might desire to be! The stress the two group word on the rope isn't each and all of the forces interior the equipment, so one group are able to word extra stress than the different. yet as quickly as you in addition to mght upload up the stress that the Earth applies to the toes each and each group, plus the stress that the communities word to a minimum of one yet another, the effect is definitely 0. thinking basically the forces on the rope, isn't thinking the the full equipment. ~WOMBAT
2016-11-25 00:18:59
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answer #5
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answered by ? 4
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I agree with the other answerers. It it affected by the gravity of the apple, but too minutely to make much different.
Consider a collision between a moving train and a fly. The fly will reduce the speed of the train, but so minutely that you won't feel it.
2006-09-06 01:48:18
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answer #6
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answered by Wundt 7
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It does, but the Earth's acceleration due to that force is infinitesimal, due to the Earth's huge mass relative to the apple, not to mention the fact that the force due to that apple is well balanced by the force of other apples and loose objects at all other points on its surface.
2006-09-06 01:46:22
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answer #7
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answered by DavidK93 7
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The crucial point to note is the mass of the apple as compared to the mass of the Earth. It negligible. So, the converse doesnt really work out.
2006-09-06 01:46:15
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answer #8
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answered by Sana 2
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By newtons laws,
F=GMm/r^2
and M>>m
M=mass of earth
m=mass ofapple
as mass of apple is negligeble when compared to mass of earth so the force with which the apple attracts the earth is negligeble.so though it attracts earth we dont feel it.
2006-09-06 03:53:18
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answer #9
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answered by Anonymous
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It does. It's just that the force from the apple on the Earth is so tiny and the Earth so massive...that the effect is negligible
2006-09-06 01:45:22
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answer #10
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answered by Morgy 4
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