I have a test today and need help finding y-intercept in a standard form equation. Help?

Question

I have to find the y-intercept in a problem that looks like this: 3x+3y=12. Also in one like this 4y-2x-3=0. How do I do that? Please show me someone.

Answer 1

First equation:To find y intercept, put the value of x = 0, so u get y = 4; so the y intercept is (0,4)

Similarly, the other one, x = 0, y = 3/4
So y-intercept (0,3/4)

Answer 2

The general equation for a line is y = mx + c where;

"y" is the y-coordinate; "x" is the x-coordinate; "m" is the gradient of the line and "c" is a constant.

The 2 main points to always remember are:
(a) At the point were the line intercepts the y-axis, x=0
(b) At the point were the line intercepts the x-axis, y=0

Therefore simply substitute for x=0 in both equations as follows:

1. 3x+3y=12; letting x=0 gives 3(0) + 3y = 12 such that 3y = 12
therefore y=4.
i.e. the y-intecept is (0;4).

2. 4y-2x-3=0; letting x=0 gives 4y - 2(0) - 3 = 0 such that 4y-3=0
therefore 4y=3 which makes y=3/4
i.e the y-intercept is (0;3/4)

So the trick is knowing and understanding the general line equation and what it means when a line intercepts an axis.

Answer 3

The y-intercept is the value of y when x=0.
Therefore the y-intercept of the first equation is
3(0)+3y=12
3y=12
y=4
and for the 2nd one
4y-2(0)-3=0
4y-3=0
4y=3
y=3/4

Answer 4

If it were an equation in the form y=x + c... c would be the y intercept. So change the equation to this form: 3y = 12 - 3x.
Divide both sides by 3
y = 4 - x. => 4 is the y intercept.

Now the other equation
4y = 2x + 3
Divide by 4 throughout
y = 1/2x + 3/4.
y intercept = 3/4

Answer 5

Both equations are linear (straight lines) that intercept (cross) the Y-axis (only at the Y-intercept). The entire Y-axis intercepts the X-axis only where x = 0. Therefore, plug 0 into your equations in place of x and solve what's left for y and you will have the value of y (the y-intercept) when x equals zero. The answer is usually in the form (x,y) so you will have an intercept at (0,?) where ? is the value of y that you solve for. It may seem a little complicated but it is just a "game" rule using special words like "intercept" but it always works once you learn the rule. Good luck on the test.

Answer 6

to find intercept of one axis u put 0 for another axis

1. 3(0)+3y=12
3y=12
y=12/3
y=4
so y intercept of 1st eq (0,4)

2. 4y-2(0)-3=0
4y-0-3=0
4y=3
y= 3/4
so y intercept for 2nd eq (0, 3/4)

Answer 7

Another method is
x/a + y/b = 1
a = x-intercept
b = y-intercept

3x+3y=12
3x/12 + 3y/12 = 1
x/4 + x/4 = 1

x-intercept = 4
y-intercept = 4

Same here
4y-2x-3=0
4y-2x = 3
-2x + 4y = 3
-2x/3 + 4y/3 = 1
x/(-3/2) + y/(3/4) = 1

x-intercept = - 3/2
y-intercept = 3/4

Answer 8

L1: 3x+3y=12
L2: 4y-2x-3=0
Let x = 0
L1: 3(0)+3y=12
3y=12
y=12/3
y= 4
L2: 4y-2(0)-3=0
4y-3=0
y-3=0-4
y-3= -4
y= 3 - 4
y= -1
then the solution set is {(4, -1)}
the answer is 4 and -1

Answer 9

the general formula for a linear eqn is y=mx+c, where c is the y-intercept. if you change the form of your formula like this,
3y= -3x + 12
divide the whole equation by 3 and you get:
y= -x + 4
therefore your y-intercept is 4

Answer 10

4y - 2x - 3 = 0
4y = 2x + 3
y = (1/2)x + (3/4)

y-intercept is (3/4)

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3x + 3y = 12
x + y = 4
y = -x + 4

y-intercept is 4