872.5 m / s
2006-09-05 19:38:05
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answer #1
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answered by Anonymous
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Most wrong answers on top!
It is true, however, that this is a trick question!
E = V * t -> distance = speed times time.
So, the speed is equal to the distance divided by the time it takes, or V = E / t.
The average speed is NOT the average OF the speeds!
You have to calculate to TOTAL time it takes to do the trips, and this is
t1 = 571,000 / 698 ~= 1469sec
t2 = 571,000 / 1047 ~= 545sec
To do the whole round trip, the plane took t1 + t2 or 2014sec
and the total distance equals twice the 571km or 1142000m
So the AVERAGE SPEED = total distance / total time or
V = 1142000 / 2014 = 567 m/sec...
2006-09-06 06:13:07
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answer #2
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answered by just "JR" 7
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Please check the answer below posted by: just "JR"
He is correct & my answer is incorrect
At first glance, this looks like a
Distance = Rate * Time (D = RT) type of problem, but it's a trick question!
The key to recognizing this is that the D always remains the same, 571 km or 571,000 m.
Since the D is the same, it's just a matter of averaging the two Rs that are given:
(698 m/s + 1047 m/s) / 2 = 872.5 m/s
2006-09-06 03:11:26
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answer #3
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answered by mrb9z 4
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The average speed of this problem is (698+1047)/2
2006-09-06 02:35:11
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answer #4
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answered by sunseekerrv 3
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837.6 meters/sec
2006-09-06 03:11:44
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answer #5
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answered by M1976 2
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is it a question ?????
2006-09-06 02:36:33
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answer #6
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answered by cool_dude 2
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