integrate logItanxIdx {0
2006-09-05
18:59:22
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12 answers
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asked by
laily
1
in
Science & Mathematics
➔ Mathematics
this means that x is between 0 and 180
2006-09-05 19:00:59 · answer #1 · answered by jrplane13 2 · 0⤊ 0⤋
It means 0 is less than x and x is less than 180.
2006-09-05 23:35:39 · answer #2 · answered by Rajeev 2 · 0⤊ 1⤋
it will be between -1
2006-09-06 01:29:23
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answer #3
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answered by ALOK 1
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0⤊
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use this process if it is indefinate else use waseem abidi process
first use integration by parts.
log|tanx|x-integration of(x(secx)^2/tanx)dx
to integrate second part put tanx=z
differetiate (secx)^2dx=dz
now substitute
integration of (tan-1zdz).[ tan inverse of t]
again use integration by parts.
answer is
x.log|tanx|-x.tan-1x+1/2.log|tanx|.
2006-09-05 20:10:55 · answer #4 · answered by krs 2 · 0⤊ 1⤋
God I hated logs. I'm sorry that I can't help you. If someone didn't break into my car and take all my books, including my math books, I would be able to help you. Good luck.
2006-09-05 19:01:24 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Solved but you have to send me some money to get the solution lol!!
2006-09-05 19:10:08 · answer #6 · answered by Anonymous 2 · 0⤊ 1⤋
Total integ: = {integ( log |tan x|), 0
II integ: x=y+pi/2, =>integ( log|tan(y+pi/2)|),0
total integ= integ1 + (-integ1)
=0
Hence d value f integ is zero.
2006-09-06 01:59:08 · answer #7 · answered by Anonymous · 0⤊ 1⤋
tell me what is the problem and I am sure that i would solve it for you
2006-09-05 19:06:21 · answer #8 · answered by leo readylove 2 · 0⤊ 1⤋
let i=int log(tanx)[0-3.14]
i=log(sinx)-log(cosx)
() represent modulus function
we know that int log(sinx)=int log(cosx)=(pi)log(1/2)
for x=[0,3.14]
thus int log(tanx)=0 for x=[0,3.14]
2006-09-05 20:13:56 · answer #9 · answered by sami1989 2 · 0⤊ 1⤋
(-I/2)*(Log[1 + I*Tan[x]]*Log[Tan[x]] + PolyLog[2, (-I)*Tan[x]]) + (I/2)*(Log[1 - I*Tan[x]]*Log[Tan[x]] + PolyLog[2, I*Tan[x]])
where I = sqrt(-1)
2006-09-05 19:04:23 · answer #10 · answered by gtn 3 · 0⤊ 0⤋