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Consider the titration of a solution of TtRd with the titrant TrNt which proceeds according to the following analytical reaction:

2TrNt + 3TtRd 5PrOd + 2H2O

The equation describing the quantitative relationship between the weight (mass) of TtRd and the concentration of TrNt which applies at the equivalence point of this titration has the following form:

MTrNt x VTrNt = (WtTtRd / Molar MassTtRd) x Stoichiometric Ratio

What is the numerical value of the Stoichiometric Ratio? Express your answer to four significant figures.
NOTE: Since stoichiometric coefficients have unlimited precision, so will the stoichiometric ratio. You are being asked to use four significant figures only out of convenience. Also, give some careful thought on your own to the units which the stoichiometric ratio should have.

2006-09-05 18:29:49 · 1 answers · asked by vem1225 1 in Science & Mathematics Chemistry

1 answers

from your reaction:

2 mole TrNt react with 3 mole TrRd
n mole TrNt react with x mole TrRd

Thus n=(2/3)x
but mole=M*V or W/MW
so n=MTrNt * VTrNt
x=WtTtRd / Molar MassTtRd
and therefore
MTrNt * VTrNt = (WtTtRd / Molar MassTtRd)(2/3)

and the ratio is 2/3=0.6667 for four significant figures.

I don't understand why you should bother calculate this ratio separetely... Usually the number of significant figures of one of the M, V and W will depend on the accuracy of the values of the rest but not on the stoichiometric coefficients.

2006-09-06 03:25:19 · answer #1 · answered by bellerophon 6 · 0 0

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