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What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 8.8 m/s when going down a slope for 6.9 s?How far does the skier travel in this time

2006-09-05 18:18:26 · 2 answers · asked by cosmos 1 in Science & Mathematics ➔ Physics

2 answers

well I'm not very certain with my answer since had been 3 month w/out practicing my physics, but I hope this helps.

I use the formula x = vt +(1/2)a(t^2)
v initial = 0 m/s
v final = 8.8 m/s
change of t = 6.9s
x = 0 + (1/2)a(6.9s)^2
a=(8.8m/s)/6.9s =1.275 m/s^2
x= (1/2)(1.275m/s^2)(6.9s)^2 = 30.35 m
Answer =30.35m
gud luck!

2006-09-05 18:34:23 · answer #1 · answered by ~tHaTaNgElFrOmAbOvE~ 1 · 0⤊ 0⤋

This sounds like homework. Got a textbook?

2006-09-06 01:21:47 · answer #2 · answered by lcmcpa 7 · 0⤊ 0⤋