A speeding motorist traveling 432000km/s passes a stationary police officer. The officer immediately begins pursuit at a constant acceleration of 36000km/s/s. How much time will it take for the police officer to reach the speeder, assuming that the speeder maintains a constant speed?
2006-09-05 17:06:28 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
In metric units, c is exactly 299,792,458 metres per second (or 299,792 km/s).
The motorist is traveling 432,000 km/s and is going faster than the speed of light. I don't think he exists (anymore).
2006-09-05 17:36:37 · answer #1 · answered by rajoohay 2 · 0⤊ 0⤋
v = u+at
v=432000 km/s
u=0
a=36000km/s^2
432000 = 0+36000*t
t = 12 seconds
very simple
2006-09-06 02:47:21 · answer #2 · answered by kaushal 1 · 0⤊ 1⤋
24 seconds
the left side is 432,000km/s*t
and right side is (1/2)36000km/s/s*t^2
2006-09-06 00:13:11 · answer #3 · answered by naked_in_lake 2 · 0⤊ 0⤋
thanx for the 2 points.
2006-09-06 00:11:50 · answer #4 · answered by Brutal honesty is best 5 · 0⤊ 1⤋
why the hell do you want to know this for? You planning a bank robbery or something?
2006-09-06 00:16:46 · answer #5 · answered by Anonymous · 0⤊ 1⤋