Thanks in advance.
2006-09-05 16:44:01 · 5 answers · asked by pnoiz1 2 in Science & Mathematics ➔ Mathematics
roots are [-b+/-(b^2-4ac)]/2a
A=-2-(4+76)/2=1-2rt5
B=1+2rt5
2006-09-05 16:47:36 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Use the quadratic equation: (-b +/- sqrt(b^2 - 4ac) ) / 2a
(-2 +/- sqrt(2^2 - 4*1*-19) ) / 2*1
(-2 +/- sqrt(4 + 76) ) / 2
(-2 +/- sqrt(80) ) / 2 --> now simplify the root: 80 = 4^2 * 5
(-2 +/- 4sqrt(5) ) / 2 --> cancel out the 2 on the botton
-1 +/- 2sqrt(5) --> there's your exact answers.
-5.47 and 3.47 --> there's your estimated answers.
2006-09-06 22:25:15 · answer #2 · answered by swimmerd76 2 · 0⤊ 0⤋
x^2 + 2x - 19 = 0
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-2 ± sqrt(2^2 - 4(1)(-19)))/(2(1))
x = (-2 ± sqrt(4 + 76))/2
x = (-2 ± sqrt(80))/2
x = (-2 ± sqrt(16 * 5))/2
x = (-2 ± 4sqrt(5))/2
x = -1 ± 2sqrt(5)
A = -1 - 2sqrt(5)
B = -1 + 2sqrt(5)
2006-09-06 00:36:02 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
(-b+b2)/2a and (-b-b2)/2a with that you d find the zeros of the equation which are are the a and b that you want i think
2006-09-05 23:51:52 · answer #4 · answered by sam (joe thornton) pro 3 · 0⤊ 0⤋
x = (-2 +/- SQRT(80))/2
which is approximately:
-5.4721
and
3.4721
2006-09-05 23:47:08 · answer #5 · answered by Orinoco 7 · 0⤊ 0⤋