One Leg of a right triangle is 12 units. Find the other two sides of the length of the hypotenuse is 33 less than twice the length of the remaining leg
2006-09-05 16:35:00 · 4 answers · asked by severedangel1776 1 in Education & Reference ➔ Homework Help
ok.. use algebra.
leg number 2 = x, hypotenuse = y.
y = 2x-33, 144 + x2 = y2.
substitute, and you get 144+x2 = 4x2-132x+1089.
convert into 3x2-132x+945=0,
divide by 3 and you get x2-44x+315=0
factor and you get (x-9)(x-35)=0
x could be 9 or 35. however, y is either -15 or 37, and none of the values are negative, so leg 2 is 35 and hypotenuse is 37. simple.
2006-09-05 16:52:32 · answer #1 · answered by fomalhaut 2 · 1⤊ 0⤋
b= the other side.
c ( hypot.) = 2b - 33
a^2 + b^2 = c^2
144 + b2 = (2b -33)^2
144 + b2 = 4b2 - 132b +1089
3b2 - 132b + 945=0
b2 - 44b + 315 = 0
I give up.
2006-09-05 17:02:56 · answer #2 · answered by 123321m 3 · 0⤊ 0⤋
let the other leg be x
12^2+x^2=(2x-33)^2
144+x^2=4x^2-132x+1089
3x^2-132x+945=0
x^2-44x+319=0
solve for x
2006-09-05 16:43:01 · answer #3 · answered by raj 7 · 0⤊ 0⤋
Why wont you ask your teacher for help, im stuck. I tried the problem myself but I just went blank
2006-09-05 16:43:14 · answer #4 · answered by Angel06 2 · 0⤊ 0⤋