(x+4)(x+2)
(x *x) + (x * 2)+(x * 4)+(2 * 4)
x^2 + 2x + 4x + 8
x^2 +(2x +4x ) +8
Answer
X^2+6x+8
2006-09-05 16:35:47
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answer #1
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answered by IRunWithScissors 3
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multiply big X by little x,then big X by -4, then +2 by x, then +2 by -4 then +2 by -4. Then add all four products to get
x^2 + -4x +2x -8. I am assuming you did not mean to capitalize one x and not the other.
2006-09-05 16:39:11
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answer #2
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answered by owali1 2
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(x+2)(x+4)
First multiply x with (x+4).After that do the same thing with 2.
=xsquard+4x+2x+8
=xsuqard+6x+8
2006-09-05 16:42:30
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answer #3
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answered by tj 2
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you take the first and the first and multiply, then the first and the last, then the last and the first, then the last and the last. so in this case, x times x is x2, x times -4 is -4x, 2 times x is 2x, and 2 times -4 is -8. then you add and get x2-2x-8
2006-09-05 16:37:12
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answer #4
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answered by fomalhaut 2
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Use FOIL
First pair
Outside pair
Inside pair
Last pair
(x + 2)(x + 4)
F = x.x = x^2
O= x . 4 = 4x
I = 2 . x = 2x
L= 2 . 4 = 8
Collect the like terms and you get x^2 + 6x + 8
2006-09-05 16:37:10
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answer #5
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answered by puhpaul 3
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(x+2)(x+4)
Use the F-O-I-L method:
F: first terms : x*x = x^2
O:outer terms: x*4 = 4x
I: inner terms: 2*x = 2x
L: last terms: 2*4 = 8
Thus, it gives you:
x^2 + 4x + 2x + 8
Then, combine like terms:
x^2 + (4x + 2x) + 8
Lastly, simplify:
x^2 + 6x + 8 (final answer!)
2006-09-05 16:42:49
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answer #6
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answered by chic_84 2
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separate out the first part of (x+2) into x and 2.
the multiply each by x-4
so u get x^2-4x
then u get 2x-8
then add those and u get x^2-4x+2x-8 and that equals
x^2-2x+8
does that help?
2006-09-05 16:39:16
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answer #7
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answered by richard w 5
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when your trying to solve a problem like this you use the foil method first inner outer last i'am not gonna tell you the answer just do what i say and you'll get answer
2006-09-05 16:41:13
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answer #8
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answered by SALAO 2
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Use the 'FOIL' method:
F- First # multiply by the second set of problem
ex. x*x
O-Outside #
I-Inside
L-last #
Keep multiplying with this step and you can't go wrong...
unless the multiplication part is wrong... Hope this helps..
2006-09-05 16:37:43
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answer #9
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answered by buntigger2 2
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FOIL method is what you want to know.
First, outer, inner last.
that is for (a + b) * (c +d), just do the:
First: a*c
Inner:b*c
Outer:a*d
Last:b*d
then, add them together
2006-09-05 16:37:25
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answer #10
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answered by rajoohay 2
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