18=2t-4
22=2t
11=t
Tori won 11 races
2006-09-05 15:01:04
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answer #1
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answered by MollyMAM 6
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11 twice is 22 - 4 = 18 tori ran 11 races
2006-09-05 22:01:23
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answer #2
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answered by psxfff123 3
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18 = 2 y - 4
2y = 18 + 4
= 22
y = 11
Tori ran 11 races. Tori did not win . Anna won , by 7 races more.
2006-09-05 22:11:37
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answer #3
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answered by Blue Shadow 2
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Let x = the number of races Tori won.
18 = 2x-4
22 = 2x
x = 11
2006-09-05 22:02:06
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answer #4
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answered by gburgmommy 3
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Tori ran 11. (11*2-4=18)
Actually, it appears to be a trick question.
2006-09-05 22:01:13
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answer #5
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answered by comeagain 2
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A=18
2T - 4 = A
2T = A + 4 (add 4 to both sides)
2T = (18 + 4) substitute the known A=18 for A
2T = 22
T = 11
Tori won 11 races.
2006-09-05 22:14:02
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answer #6
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answered by Anonymous
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You put a twist on the question....not how many races did Tori run but how many did she win. There's no way to compute that.
2006-09-05 22:03:02
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answer #7
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answered by Laura 6
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18=2x-4 you add 4 on both sides 18+4=2x-4+4
-4 and +4 cancel each other out so it becomes zero.18+4= 22
22=2x you divide by 2 to get x by itself. 2÷2=1 1by x = x and 22÷2=11 so the answer is 11.
2006-09-05 22:08:35
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answer #8
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answered by sabrina 3
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its 7 becuase anna ran 18 and tori ran 4 less... so that is 14 and you divide that inhalf and you get 7
2006-09-05 22:00:55
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answer #9
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answered by help 1
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let Torri=x
18(anna)= 2x-4
subtract 4 from both sides
14=2x
divided 2 from both sides
x=7
2006-09-05 22:02:15
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answer #10
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answered by yellowskinnedguy 3
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