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As far as my research goes, as temperature goes up, density goes down, but I need the specifics for volume and mass related to temperature, and I can't find them anywhere.

If anybody has the answer on a good multi-purpose chem website, please link to it!

2006-09-05 13:44:13 · 6 answers · asked by Alice 2 in Education & Reference Homework Help

Edit: I did check my textbook, but thanks for the help.

2006-09-05 13:58:35 · update #1

6 answers

If pressure is constant, then when temperature increase volume also increases. Mass is always constant regardless of temperature, pressure, etc. Therefore when temperature increases density decreases because density = mass (constant) divided by volume (decreasing).

2006-09-05 13:58:45 · answer #1 · answered by tsihilin 3 · 0 0

No change in mass, volume goes up.

This should be in your text book, luv. Have you tried looking there?

Edit: The volume of water will also generally increase as the temperature does, except when the water is between 0 and 4C. At this point, an increse in temperature will result in a decrease in volume, due to something called the Hydrogen Bond. I doubt you need to worry about that, though.

2006-09-05 13:51:31 · answer #2 · answered by Anonymous · 0 0

A substance’s volume usually increases with temperature, except in the case of water in which the opposite occurs. Think about it. As something heats up the molecules speed it and spread further apart which is why a solid will turn into a liquid and a liquid into a gas. I’m not sure about mass, though.

2006-09-05 13:50:23 · answer #3 · answered by blah1 2 · 0 0

As the IQ goes down, the Density goes up. This is a proven negative correlation.

2006-09-05 13:47:54 · answer #4 · answered by Autumn Harvest 2 · 0 0

the higher the temperature the more space between that atoms, something to do with electrons going faster. its been a long time since i had to think about that.

2006-09-05 13:51:35 · answer #5 · answered by Matthew V 1 · 0 0

thats a hard one

2006-09-05 13:46:15 · answer #6 · answered by alan d 2 · 0 0

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