Here's an easy way to remember it. The quadratic formula is
[-b +/- sqrt(...)] / (2a)
Now, forget the plus or minus stuff, and what you're left with is
-b / (2a)
That's the line of symmetry (and you can also use it to find the vertex).
For your problem, -b/(2a) = -3/8
x = -3/8 is the answer.
2006-09-05 12:54:22
·
answer #1
·
answered by bpiguy 7
·
0⤊
0⤋
differientiate y=4x^2 + 3x + 8,
you get , dy/dx= 8x + 3
to find the min pt so that you can can find the line os symetry equate the whole thing to zero,
therefore, 8x= -3, x= -3/8
draw a vertical line up the point x= -3/8 and you get the line of symetry
2006-09-06 07:54:20
·
answer #2
·
answered by superlaminal 2
·
0⤊
0⤋
y = 4x^2 + 3x + 8
x = (-b)/(2a)
x = (-3)/(2(4))
x = (-3/8)
ANS : (-3/8)
2006-09-06 00:27:14
·
answer #3
·
answered by Sherman81 6
·
0⤊
0⤋
you find it by doing your own homework and paying attention in class
2006-09-05 19:46:18
·
answer #4
·
answered by Punchy 2
·
0⤊
0⤋