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4 answers

Here's an easy way to remember it. The quadratic formula is

[-b +/- sqrt(...)] / (2a)

Now, forget the plus or minus stuff, and what you're left with is

-b / (2a)

That's the line of symmetry (and you can also use it to find the vertex).

For your problem, -b/(2a) = -3/8

x = -3/8 is the answer.

2006-09-05 12:54:22 · answer #1 · answered by bpiguy 7 · 0 0

differientiate y=4x^2 + 3x + 8,
you get , dy/dx= 8x + 3
to find the min pt so that you can can find the line os symetry equate the whole thing to zero,
therefore, 8x= -3, x= -3/8

draw a vertical line up the point x= -3/8 and you get the line of symetry

2006-09-06 07:54:20 · answer #2 · answered by superlaminal 2 · 0 0

y = 4x^2 + 3x + 8

x = (-b)/(2a)
x = (-3)/(2(4))
x = (-3/8)

ANS : (-3/8)

2006-09-06 00:27:14 · answer #3 · answered by Sherman81 6 · 0 0

you find it by doing your own homework and paying attention in class

2006-09-05 19:46:18 · answer #4 · answered by Punchy 2 · 0 0

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