A 20-ft board is cut into three pieces. The second is three times as long as the first. The third piece is twice as long as the second. Find the lengths of the pieces.
2006-09-05 12:41:53 · 7 answers · asked by daya 1 in Education & Reference ➔ Homework Help
Solve for X:
X + 3X + 2(3X) = 20.
4X + 6X = 20.
10X = 20.
X = 2 (first board)
3x2 = 6 (second board)
6 x 2 = 12 (third board)
Check answer: 2 + 6 + 12 = 20
2006-09-05 12:47:49 · answer #1 · answered by jurydoc 7 · 0⤊ 0⤋
first piece is 2, second piece is 6, third is 12. all together add up to 20 feet
2006-09-05 12:55:00 · answer #2 · answered by scooby doo 3 · 0⤊ 0⤋
in case you have a board it is 20ft, you will discover the lengths making use of right here approach: The board is decrease into 3 products A, B and C, so: A + B + C = 20 (the lengths of the three products equivalent 20ft) If the 2nd piece, B, is thrice as long because of the fact the 1st, A, you have: B = 3A If the 0.33 piece, C, is two times as long because of the fact the 2nd, B, you have: C = 2B Substituting B into the equation, you have: C = 2(3A) = 6A (0.33 piece is six cases as long as first piece) Now you have all in terms of A: A + B + C = 20 A + 3A + 6A = 20 upload like words: 10A = 20 Divide by making use of 10: A = 2ft Plug A into equation: B = 3A B = 3(2) = 6ft Plug B into equation: C = 2B C = 2(6) = 12ft The lengths are: 2ft, 6ft, 12ft
2016-10-14 08:56:22 · answer #3 · answered by wishon 4 · 0⤊ 0⤋
The first piece = x
The second piece = 3x
The third piece = 2(3x)
They all add up to 20, so...
x + 3x + 6x = 20.
10x = 20.
Solve and substitute.
2006-09-05 12:43:56 · answer #4 · answered by Steven Procter 2 · 0⤊ 0⤋
x(piece 1)+2x(piece 3)+3x(piece 2)=20(total length)
6x=20
x=10/3ft.=piece 1
2x=20/3ft.=piece 3
3x=10ft. = piece 2
2006-09-05 12:47:47 · answer #5 · answered by Mike R 4 · 0⤊ 0⤋
2 feet, 6 feet, 12 feet.
2006-09-05 12:45:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋
do your own homework
2006-09-05 12:43:11 · answer #7 · answered by Punchy 2 · 0⤊ 0⤋