kent is three years older than his sister debbie. the sum of their ages is 105. find their ages.?

Question

wats the answer. can u show me how to do it also? please.

Answer 1

kent is 54, debbie is 51 105-3=102, divided by 2=51 that is Debbie's age 51+3+54, that is Kent's age

Answer 2

Okay.

Let's say Debbie's age is represented by the variable X.
That means Kent's is (X+3) because he's three years older.\
The sum of their ages is 105. Let's make this into an equation:

Debbie's age + Kent's age = 105
X + X+3 = 105
2X + 3 = 105
2X = 102
X = 51

Debbie's age was represented by X, so that means she is 51 years old. Kent's age was represented by (X+3), which is now (51+3) which is 54.

51+54=105.

There you have it.

Answer 3

51 and 54. = 105

Subtract 3 from 105 = 102. Divide by 2 = 51. the sister's age. Add 3 for Kent.

Answer 4

105-3=102

102/2=51now their ages are equal

since kent is 3 years older than debbie, just add 3 to 51=54

Answer 5

First take 3 away from 105, to represent kents age. then divide 102 by 2 to get 51. Then you add 3 back onto on of those 51's and you get kents age to be 54 and his sister to be 51.

Answer 6

51 and 54.

Subtract 3 from 105 ( = 102). Divide by 2 ( = 51). That's the sister's age. Add 3 (obviously) to get Kent's.

Answer 7

The answer is that Kent is 54 and Debbie is 51

Answer 8

Ken = D+3
Debbie = D
D+D+3=105
D+D+3-3=105-3
D+D=102
2D=102
D=51 (Debbie)
Therfore, Ken =54

Answer 9

Kent is 54 and Debbie is 51, I did it in my head so can't really show you how

Answer 10

k = d +3 (1)
k+d=105 (2)
(2) -(1)

d= 105 - d -3
2d=102
d=51, k=54