English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

How do find this answer?

2006-09-05 12:02:38 · 3 answers · asked by RED MIST! 5 in Science & Mathematics Chemistry

3 answers

First note what type of reaction occurs:

NH3 + H20 <---> NH4 + 0H-, acts to create more OH- so it is a base, or since NH3 accepts a proton it acts as a base.

Need to know the Kb = [NH4+][OH-]/[NH3] = 1.8 * 10^-5

This is a small value so your NH3 concentration is not going to change much due to ionization, so we can plug in 0.6 for [NH3]

Kb = 1.8 * 10^-5 = [NH4+][OH-]/[0.6], we let x =[ NH4+] which should also have the same concentration as [0H-] so the equation becomes:

Kb = 1.8 *10^-5 = x^2/0.6 solve for x = 2.54 * 10^-2 = [0H-]

Since Kw = [H+][OH-] = 10^-14, we find the [H+] = 3.93 *10^-13,
the -log(3.93 * 10^-13) = 12.4

Please check for errors.

2006-09-05 13:18:40 · answer #1 · answered by Anonymous · 0 0

pH and pOH can be related by the following equation
pH + pOH =14
1 mole of aqueous ammonia(ammonium hydroxide) on dissociation produces 1 mole of ammonium ions and 1 mole of hydroxide ions.The mole ratio between the aqueous ammonia and the hydroxide will be 1:1,therefore the number of moles of the hydroxide ions is 0.6 moles. The pOH can be calculated by
pOH= -log[OH-]
= - log[0.6]
= 0.2
therefore the pH of 0.6M NH3 =14 - 0.2
=13.8

2006-09-05 19:40:04 · answer #2 · answered by Albert F 2 · 0 0

It would be acidic

2006-09-05 19:05:00 · answer #3 · answered by josh_patriots 2 · 0 1

fedest.com, questions and answers