Caclulate the partial pressure.?

Question

For this reaction, calculate the partial pressure of Br2 if p(NO) = 2.0 atm and, P(NOBR) = 5 atm, and Kp = 9.182.

NO(g) + Br2(g) <-> NOBr(g).

And please give a detailed description of how you do it.

Answer 1

2NO(g) + Br2 (g) <=> 2NOBr(g)

Therefore Kp= P(NOBr)^2 / (P(NO)^2 * P(Br2)) =>

P(Br2)= P(NOBr)^2 / (P(NO)^2 * Kp) =
= (5^2)/((2^2) * 9.182)=
= 0.68 atm

provided that Kp= 9.192 atm^-1

Answer 2

Your equilibrium equation is not balanced.