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divide and simplify:

w to the forth DIVIDED by x to the NEGATIVE square


is the answer w6?!?!

if not..please tell me the correct answer and explaion it!!!

if you have any questions....message me from my profile (email contact only)...THANKS!

2006-09-05 08:11:18 · 7 answers · asked by Lina 4 in Science & Mathematics Mathematics

7 answers

if you meant w to the 4th divided by w to the negative 2nd then the answer is w^6:
(w^4)/(w^(-2)) = w^(4-(-2)) = w^(4+2) = w^6

The way you have it written, though is (w^4)/(x^(-2)) = (w^4)*(1/(x^(-2)) = (w^4)(x^2)

2006-09-05 08:17:27 · answer #1 · answered by godmike 2 · 0 0

w^4/x^-2=w^4(x^2)=w^4x^2
when you take an exponential quantity from the
numerator to the denominator or vice versa
the sign of the power changes
so 1/X^-2=x^2

2006-09-05 08:17:04 · answer #2 · answered by raj 7 · 0 0

No. Bring the x ^ -2 to the numerator to get w^4x^2.

2006-09-05 08:17:26 · answer #3 · answered by steiner1745 7 · 0 0

w^4/x^-2=w^4x^2 is correct only if x is not equal to zero.

w^4/x^-2 is not defined if x=0, but w^4x^2=0 for x=0.

2006-09-05 08:35:50 · answer #4 · answered by Wonko der Verständige 5 · 0 0

With no brackets I assume this is to be read as:

(w^4)/(x^(-2))

Which is equal to (w^4)*(x^2)... And there's really nothing else worth doing to this expression... Unless theres more information about x and w...

2006-09-05 08:19:00 · answer #5 · answered by kuxuru 3 · 0 0

w^4 / x^-2

Well, here's a little info for you...

A negative power basically means it gets flipped over the fraction sign and the negative is removed...

w^4 / x^-2
w^4x^2

2006-09-05 09:13:45 · answer #6 · answered by Anonymous · 0 0

idk, i'm only in Algebra 1, that's kinda way over my head. But thnx for the points!

2006-09-05 08:26:34 · answer #7 · answered by hello. 2 · 0 0

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