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Ok my teacher went to a meeting and had to do these problems and when she got back she gave it to us.

ok instructions she said we can use any math tools like parenthese or other math tool.

here are the problems and i did some by myself

i mena like find a way to get 6 using each three numbers in every problem

1 1 1=6

2 2 2=6
2x2+2

3 3 3=6
3x3=9-3=6

4 4 4=6

5 5 5=6
5/5=1+5

6 6 6=6
6/6=1x6=6

7 7 7=6
7-(7/7)
7-1
=6

8 8 8=6

9 9 9=6

2006-09-05 06:33:57 · 3 answers · asked by JANET 1 in Education & Reference Homework Help

3 answers

factorial operator is !...
(1+1+1)! = (3)!
1x2x3 = 6

sqrt (4) = 2
sqrt (4) + sqrt (4) +sqrt (4) = 6

8^2 = 64
cube root (64) = 4
sqrt (4) = 2
sqrt(cuberoot(8^2)) = 2
sqrt(cuberoot(8^2)) + sqrt(cuberoot(8^2)) + sqrt(cuberoot(8^2)) = 6

9^2 = 81
81 / 9 = 9
9 - sqrt (9) = 6
((9^2) / 9) - sqrt (9) = 6

2006-09-05 07:04:31 · answer #1 · answered by Professor 3 · 0 0

1 1 1=6
(1+1+1)! = 6
3!=6
3 * 2 * 1 = 6
6 = 6
---
4 4 4=6
sqrt 4 + sqrt 4 + sqrt 4 = 6
(sqrt means square root)
2 + 2 + 2 = 6
6=6
---
8 8 8=6
(round(8-.8-.8)) = 6
(round(6.4)) = 6
6=6
---
9 9 9=6
(sqrt 9)! * 9/9 = 6
3! * 1 = 6
3 * 2 * 1 = 6
6=6

2006-09-05 07:01:54 · answer #2 · answered by ³√carthagebrujah 6 · 0 0

4+4-sqrt4(2)
9+9/sqrt9(3)

2006-09-05 06:59:28 · answer #3 · answered by sappergary 2 · 0 0

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