7(3x + 4) = 8(2x + 5) + 13
2(x - 3) - 3(x + 5) = 3(x - 2) - 7
I do not want anyone to do the problems for me just explain what process to use, I am so confused.
2006-09-05 06:30:08 · 5 answers · asked by DEE L 2 in Education & Reference ➔ Homework Help
Start by multiplying the number outside the parentheses by each of the factors inside the parentheses. This will get rid of the parentheses and give you something that looks more like a solvable equation. Then, simply solve for "x" by isolating it on one side of the "=" sign.
2006-09-05 06:32:11 · answer #1 · answered by jurydoc 7 · 0⤊ 1⤋
7(3x+4)=8(2x+5)+13
21x+28=16x+40+13
21x+28=16x+53
21x-16x=53- 28
5x=25
x=5
2(x- 3)- 3(x+5)=3(x- 2)- 7
2x- 6- 3x- 15=3x- 6- 7
- x- 21=3x- 13
- 21+13=4x
- 8=4x
x=-2
2006-09-05 13:45:16 · answer #2 · answered by denise p 4 · 0⤊ 0⤋
First use the distributive property:
i.e. 7*3x + 7*4, do the same on the other side, then do basic math to simplify, then cancel out by doing the opposite, until you're left with x
2006-09-05 13:38:32 · answer #3 · answered by Oscar 3 · 0⤊ 0⤋
Step 1. Clear the brackets by multiplying the figures inside the brackets.
Step 2. keep variables on one side and sum of numbers on another side.
step3 Divide sum by variables and you will get the answer.
2006-09-05 13:37:30 · answer #4 · answered by Anonymous · 0⤊ 1⤋
removing the parenthese
21x+28=16x+40+13
transposing
21x-16x=40+13-28
5x=25
x=5
2.removing the brackets
2x-6-3x-15=3x-6-7
transposing
2x-3x-3x=-6-7+6+15
-4x=8
x=-2
2006-09-05 13:34:39 · answer #5 · answered by raj 7 · 0⤊ 2⤋