2006-09-05 04:05:43 · 2 answers · asked by sancho10111101111011101111101111 1 in Science & Mathematics ➔ Chemistry
The first step is protonation of the alcohol, ROH to give ROH2+. For R=t-Butyl, the next step is RROH2+.--> R+ + H2O. After that a number of different things can happen depending on conditions. The usually desired reaction is given by
R+ + Br- ---> RBr. Other possibities include reaction with more ROH to give the ether (R+ ROH ---> R2OH+, R2OH+ --> R2O + H+). It is also likely that at least some of the t-Butyl cation will lose a hydrogen ion to give 2-methylpropene.
2006-09-05 04:37:39 · answer #1 · answered by Richard 7 · 0⤊ 0⤋
alcohol gets protonated and makes the OH into OH2 which is a better leaving group. than the Br- attacks and you get the bromination product.
HBr is a strong acid fyi
2006-09-05 05:36:03 · answer #2 · answered by shiara_blade 6 · 0⤊ 0⤋