2006-09-05 03:36:11 · 14 answers · asked by z 2 in Science & Mathematics ➔ Mathematics
Express like this:
f^(-1)(x)=x^(1/2)
2006-09-05 03:39:49 · answer #1 · answered by albert 5 · 0⤊ 1⤋
Question: What is the inverse of f(x) = x^2
Ans:
Let y = x^2
To find the inverse change x with y and y with x
x = y^2
or y = sq-rt x= (x)^1/2 this is the inverse of f(x) = x^2
2006-09-05 05:15:32 · answer #2 · answered by Amar Soni 7 · 0⤊ 0⤋
The inverse of f(x) = x^2
x=f(x)^1/2.
2006-09-05 03:50:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
x=f(x)^1/2
2006-09-05 03:42:25 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
it is x^(1/2)
2006-09-05 03:41:21 · answer #5 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
if f(x) = x^2
then get the variable in terms of the function. i.e,
x= [f(x)]^(1/2)
then replace x with f^(-1) (x) , i.e, the inverse function,
and f(x) with the variable x
then, f^(-1) (x) = x^(1/2)
there you go, the square root of x is the inverse function.
Hope this helps!
2006-09-05 04:52:21 · answer #6 · answered by yasiru89 6 · 0⤊ 0⤋
2^x=(x)f
2006-09-05 03:43:05 · answer #7 · answered by kami_morris 2 · 0⤊ 1⤋
f(x)=(x^2)^(-1)
=1/(x^2)
2006-09-05 03:53:33 · answer #8 · answered by maya 3 · 0⤊ 0⤋
If you consider f(x) to have its full domain (-infty, infty), there is no inverse function because f(x) is not one-to-one. If you restrict the domain to [0,infty), the inverse function is sqrt(x). If you restrict the domain to (-infty, 0], the inverse function is -sqrt(x). Your choice.
2006-09-05 03:39:57 · answer #9 · answered by mathematician 7 · 2⤊ 0⤋
1\x^2
x ^ -2
if you multiply you get x^2*x^-2
add and you get x^0
that = 1
which is what inverse means
2006-09-05 03:46:46 · answer #10 · answered by bob h 3 · 0⤊ 0⤋