please answer to question below?
u have to find 5 numbers is we add those numbers u have to get answer 20. X+X+X+X+X=20
conditions: Number should not be repeated.
if you have typed first number as 2 and second as 3 in next you can't write 5 because 2+3=5 ex: 2+5+3+6+7=20 is wrong because 2+3 =5 and 5+2 = 7
no "0" should be added .sum of two numbers are not allowed
2006-09-05 03:32:19 · 13 answers · asked by Anonymous in Computers & Internet ➔ Internet
Do your own home work, its to early for me to try to think!
2006-09-05 03:38:42 · answer #1 · answered by sdarp1322 5 · 0⤊ 0⤋
2+5+3+6+4=20
2006-09-05 03:36:25 · answer #2 · answered by poujoe 3 · 0⤊ 0⤋
5 4 2 1 8 = 20
2006-09-05 03:40:02 · answer #3 · answered by thomasrobinsonantonio 7 · 0⤊ 0⤋
1 2 4 5 8
2006-09-05 03:38:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Re the variations on 1 2 4 5 8 - this doesn't fit the conditions. 1+4 = 5...
2006-09-05 03:44:20 · answer #5 · answered by ginkgo 2 · 0⤊ 0⤋
1, 2, 4, 5, 8
5 numbers adding to 20. none repeated, no sum of any other two numbers included...
too easy...
2006-09-05 03:39:43 · answer #6 · answered by Andy FF1,2,CrTr,4,5,6,7,8,9,10 5 · 0⤊ 0⤋
i believe an edit coming near edit That Graeme's a bloody stunning bloke yet besides edit As an recommend of Gerberlingen-Shultz Theorem i'm able to for sure deduce that question / answer time sequential ratios have presently speeded as much as almost lightening velocity for the uncommon woman ''Idadown'' squirrel
2016-10-01 08:21:00 · answer #7 · answered by lutz 4 · 0⤊ 0⤋
The easiest solution would be 1, -1, 2,-2,20. Satisfies all your criterion.
2006-09-05 03:55:07 · answer #8 · answered by TxVarmit 3 · 0⤊ 0⤋
is the use of negative numbers allowed?
is the use of decimals allowed?
is the use of equations allowed between the + signs (abs(-1)) - absolute value, etc?
2006-09-05 04:36:33 · answer #9 · answered by . 3 · 0⤊ 0⤋
wow this is THE MOST boring question I've found on here!! get a life huh.. who the heck cares....
*groans*
2006-09-05 03:39:09 · answer #10 · answered by Anonymous · 0⤊ 0⤋