H2SO4 + 2NaOH --> Na2SO4 + 2H20
MαVα / MβVβ = 1/2 M=molarity α=acid
2(ΜαVα) = ΜβVβ V=volume β=base
Therefore 2 mole of sulphuric acid is required to neutralise 1 mole of sodium hydroxide ??????????
Is This Logical??????
2006-09-05 01:26:39 · 3 answers · asked by Omega_sages 2 in Science & Mathematics ➔ Chemistry
The equation is
a(acid)* M(acid)* V(acid)= a(base)* M(base)* V(base)
where a(acid) and a(base) is the valency of the acid and base respectively.
In this particular case
2*M(acid)* V(acid)= M(base)* V(base)
which means that you need NaOH equal to twice the moles of H2SO4 and not the other way around. You just misinterpreted the equation.
2006-09-05 01:40:19 · answer #1 · answered by bellerophon 6 · 1⤊ 0⤋
No it is not logical. According to your equation, 2 moles of sodium hydroxide is required to react with one mole of sulfuric acid.
2006-09-08 17:00:21 · answer #2 · answered by Richard 7 · 0⤊ 0⤋
H2SO4 is diprotic so you need twice as much base to neutralize it. you just misinterprited the equation.
2006-09-12 12:44:10 · answer #3 · answered by shiara_blade 6 · 0⤊ 0⤋