Trig help Please...sec 5.9*...=cos 5.9* ^-1???

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Trig help Please...sec 5.9...=cos 5.9 ^-1???

TI-83 Plus...is this right? I can't find notes on it! If not, what is the right formula to enter into the calculator?

2006-09-04 17:49:45 · 4 answers · asked by Helzabet 6 in Science & Mathematics ➔ Mathematics

Thanx Texas! I remember now.....

2006-09-04 18:01:00 · update #1

sec x = 1/cos x

2006-09-04 17:57:37 · answer #1 · answered by thebestbotintexas 2 · 1⤊ 0⤋

Yes, it is. The definitions are
sec(x) = 1/cos(x)
csc(x) = 1/sin(x)
cot(x) = 1/tan(x)

Doug

2006-09-05 01:00:19 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋

sec 5.9=1/cos 5.9=cos5.9^(-1)

2006-09-05 04:37:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋

34.81

2006-09-05 00:56:26 · answer #4 · answered by Columbus614Ohio 2 · 0⤊ 0⤋