The actual question is:
A second train leaves Chicago for NY 2 hours after the First train. The First train travels at an average speed of 65mph. How long will it take the second train to overtake the first train if the second train travels at an average speed of 90mph?
I got the equation which is:
90t = 65(t + 2)
which got me to t=5.2
My question is how much is that in Hours and minutes?
Is it 5 hours and 20 minutes???
2006-09-04 16:42:35 · 5 answers · asked by xashleyleyx 4 in Education & Reference ➔ Homework Help
.2x60minutes=12 minutes
So it would be 5 hours 12 minutes.
2006-09-04 16:45:29 · answer #1 · answered by just♪wondering 7 · 0⤊ 0⤋
it's 5 and 2/10 of an hour which means that it's 5 hours and 12 minutes
2006-09-04 16:46:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The answer is 5 hours and 12 minutes.
2006-09-04 16:49:01 · answer #3 · answered by owali1 2 · 0⤊ 0⤋
let say x is a location where they meet and h is how long it will take.
so equation for train 1 is x = 65h + 130, 130 because it depart 2 hours earlier than train 2, so 65x2 = 130
equation for train 2 is x = 90h
by combining both equation
90h = 65h + 130;
we can solve h = 5.2
so you are correct at this point.
h = 5.2 hours means 5 hours 0.2x60 minutes
so 5hours 12 minutes.
2006-09-04 17:31:56 · answer #4 · answered by (^___^) 2 · 0⤊ 0⤋
90t= 65(t+2)
90t = 65t+130
25t = 130
t = 5.2 hours
.2* 60 min = 12 min
therefore it takes 5 hours and 12 minutes
2006-09-04 16:48:18 · answer #5 · answered by Brian F 4 · 0⤊ 0⤋