would you solve x^2=x to end up with the answer x=1 and x=0?
It's the example to a problem I'm working out....
2006-09-04 16:07:34 · 8 answers · asked by egyptsprincess07 3 in Science & Mathematics ➔ Mathematics
bring the x to the other side and factor the equation. x^2 - x = 0. You can factor that to x*(x-1). Which gives you the answers of x=1 or x=0.
2006-09-04 16:11:31 · answer #1 · answered by wildstar_2 6 · 0⤊ 0⤋
To start I will show the form you currently have written.
x^2=x
Subtract x from both sides to get the following.
x^2-x=0
Factor x to get
x(x-1)=0
Now just plug in the values that make the statement above true.
Let x=1
1(1-1)=0
1(0)=0 this is true
Let x=0
0(0-1)=0
0(-1)=0 this is true
So the zeros are x=1 & x=0
2006-09-04 23:27:01 · answer #2 · answered by Scott S 4 · 0⤊ 0⤋
x^2 = x
add -x on both sides
x^2-x =0
facroring
x(x-1) =0
x= 0 or x-1 =0 that is x =0 or 1
2006-09-05 00:16:29 · answer #3 · answered by Mein Hoon Na 7 · 0⤊ 1⤋
x^2=x
x^2 - x = 0
(x) (x -1) = 0
find the roots
what makes this equation = 0
when x = 0 and x = 1
2006-09-04 23:17:20 · answer #4 · answered by Alixa 1 · 1⤊ 1⤋
x^2 = x
x^2 - x = 0
x(x-1)=0 or (x+0)(x-1) = 0
therefore, x = 0 or 1
2006-09-04 23:12:15 · answer #5 · answered by Anonymous · 1⤊ 1⤋
Hi. I agree with Wildstar 2.
2006-09-04 23:12:25 · answer #6 · answered by Cirric 7 · 0⤊ 1⤋
well that seems like something you should have figured out a year or two ago......
2006-09-04 23:15:49 · answer #7 · answered by Anonymous · 1⤊ 1⤋
u gave me a problem....
2006-09-04 23:12:38 · answer #8 · answered by Anonymous · 0⤊ 2⤋