0.0334 mol C, 0.1000 mol H, and 0.0167 mol O
i just dont get how to do this, please walk me through.
2006-09-04 15:49:42 · 3 answers · asked by cheezzznitz 5 in Science & Mathematics ➔ Chemistry
THANKS EVERYONE. CORRECT ANSWER HAS BEEN SAID. MEANWHILE, ANSWER MY OTHER CHEMISTRY QUESTIONS.
2006-09-04 16:03:41 · update #1
choose the smallest mol.
use that as a factor.
divide the three with the smallest factor.
0.0334/ 0.0167 = 2
0.1000 / 0.0167 = 5.98.... = 6
0.0167 / 0.0167 = 1
thus you would have C2H5OH, which is ethanol!
2006-09-04 15:54:15 · answer #1 · answered by maczh2002 2 · 1⤊ 0⤋
Basically, you want to know how many molecules of each in the compound. So, since atoms can't exist in numbers smaller than one, you find out how many of the others are there when there is one atom of the smallest amount of moles. So, you divide 1 by the smallest number of moles, in this case 0.0167 for O; 1/0.0167=59.88023 round up to 60, so this is your multiplication factor-you need to multiply the other two mol numbers by 60 to get how many atoms of each will be there when there for every one atom of O. So, 60*0.0334=2 so 2 atoms of C, and 60*0.1000=6 so 6 atoms of H. Putting that together, the empirical formula is C2 H6 O
2006-09-04 23:00:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
find the ratio between the 3. divide the larger numbers by the smallest.
the ratio between C and O is .0334/.0167=2
ratio btwn H and O is .1/.0167 is about 5.9 something, but you round to 6
be careful when you do these problems that you dont round too much, esp when the ratio is 1/6
so the emp formula is C2H6O
2006-09-04 22:54:38 · answer #3 · answered by Anna 2 · 0⤊ 0⤋