i got 25.9
are my significant figures wrong?
teacher says its wrong. what is correct answer?
2006-09-04 15:40:24 · 5 answers · asked by cheezzznitz 5 in Science & Mathematics ➔ Chemistry
andrew b, you forget that iron III phosphate is Fe3(Po4)3
2006-09-04 15:50:46 · update #1
the answer is 8.64g. 3 sig figs.
1 Fe=55.845g/mol
1 P=30.97g/mol
4 O=16*4=64g/mol
FePO4=150.815g/mol
150.815g/mol * 0.0573= 8.6416995= 8.64g
2006-09-04 15:49:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You first ought to be certain the burden of one mole of C8H18. bypass to the periodic table to get the weights of all the climate on your compound then upload them. C = 12 grams x 8 = ninety six grams H = a million gram x 18 = 18 grams finished = ninety six + 18 = 114 grams in a single mole. in case you have 5.9 moles, multiply this with the help of the burden of one mole (114 grams) = 672.6 rounded to 673 grams in 5.9 moles. Your answer is D.
2016-12-18 05:01:47 · answer #2 · answered by ? 4 · 0⤊ 0⤋
i dont know what the molar mass of iron 3 phosphate is, but what it is, ill denote as MM, you do
MM (which is also grams/mol) times mols. (the moles cancel out to give grams as your unit-how you check if you did the process right)
i think your sig figs are correct, but the calculations are wrong. i can't read my calculator screen very well but i think it says something close to 8.
2006-09-04 15:50:29 · answer #3 · answered by Anna 2 · 0⤊ 0⤋
Is this a trick question? 0.0573 milliliters =zero ounces. Zero ounces converted to grams =zero
2006-09-04 16:08:29 · answer #4 · answered by pipejetter 2 · 0⤊ 0⤋
151 x 0.0573 = 8.65
maybe
2006-09-04 16:03:46 · answer #5 · answered by bay-from-indonesia 1 · 0⤊ 0⤋