How many moles of ammonium ions are in 0.705 g of ammonium carbonate?

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How many moles of ammonium ions are in 0.705 g of ammonium carbonate?

I got 1.41
my teacher says its wrong. Wrong significant digits, or what?

2006-09-04 15:39:49 · 2 answers · asked by cheezzznitz 5 in Science & Mathematics ➔ Chemistry

if wrong, what is correct answer?

2006-09-04 15:40:41 · update #1

ammounium carbonate is (NH4)2(CO3)

2006-09-04 16:04:28 · update #2

2 answers

Ammonium carbonate is (NH4)2CO3
and its molecular mass is 2 x (14 + 4) + 12 + 48 = 96
So n = 0.705/96 = 0.00734375 mole = 7.34 mmole

2006-09-04 16:13:29 · answer #1 · answered by dactylifera001 3 · 0⤊ 0⤋

find the molar mass of al co3
and divide the .705 by it
so its grams/ molar mass = moles (because molar mass=grams per mole, so the grams unit would cancel out

2006-09-04 22:56:58 · answer #2 · answered by Anna 2 · 0⤊ 0⤋