Y is between X & Z. XY=4x+2 and YZ=5x and XZ=56. Find XY?

Question

Can someone walk me through this and tell me how they got the answer. Please dont just give me the answer. Show me the work.

I dont know how to do this.

Answer 1

Y is between X and Z, so the line would be

X----Y----Z

XY (half the line) is (4x + 2)

YZ (the other half) is (5x)

This means XZ (the whole line) is XY + YZ:

XZ = (4x + 2) + (5x)

The problem gives you XZ = 56, so you have two things that equal XZ. Set them equal to each other:

(4x + 2) + (5x) = 56

9x + 2 = 56

9x = 54

x = 6

You're looking for the measurement XY, and you were given:

XY = 4x + 2

So plug in x=6, and you get:

XY = 4(6) + 2

XY = 26

Answer 2

XY+YZ = XZ (X,Y, and Z are points on a number line with Y being inbetween X and Z.)

therefore: 4x+2 + 5x = 56
9x + 2 = 56
9x = 54
x = 6
thus
XY = 4(6)+2
XY = 24+2
XY = 26

and if you wanted to know YZ= 30

Answer 3

Do you want to know what X and Y are individually or is it a trick question where XY is 4x + 2?

Answer 4

see u have three equations, total of 3 variables.

for instance, if u take the 2nd one, then yz=5x. OR y=5x/z. substitute in the first one.

u'll get another eqn (4) in x&z now, whicih u can use wit ur old eqn 3 and get val of x &z.. like this solve the 3 eqns to get another set of 3 eqns.. and then solve them (elimination method) to get the answer.

sorry, i'm too lazy to calc. but this is the method.

Answer 5

u really need a graphing calculator