Im having problems with my homework, its on algebra 2 and I cant find the answer. Here is the question:
write an equation which, when paired with -2x+3y=12 to form a system, has the given number of solutions.
a. exactly one solution.
b. No solution.
c. infinitely many solutions.
the questions comes from the McDougal Littell Algebra 2 book. page 191, question #13.
2006-09-04 14:56:46 · 3 answers · asked by TrillVille 2 in Education & Reference ➔ Homework Help
b) No solution means the coefficients of x and y will be the same, but the constant will be different
-2x + 3y = 5 or -2x + 3y = 6 or -2x + 3y = 0
c) Just multiply the whole equation by any number.
Say you like the number 7.
-2x(7) + 3y(7) = 12(7)
-14x + 21y = 84
or -4x + 6y = 24 (I multiplied the equation by 2)
a) Just change the coefficients of x and y.
x + y = 3
or x - y = 8 or 2x - 11y = 0
2006-09-04 14:59:54 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
a) y=0, or y=whatever, or x = whatever
b) -2x+3y=whatever; but whatever not 2
b) (-2x+3y)whatever=12*whatever
2006-09-05 04:23:11 · answer #2 · answered by gjmb1960 7 · 0⤊ 0⤋
Try using this
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=mathcom&s1=equations&s2=solve&s3=basic
http://www.math.com/students/solvers/algebra/algebra.htm
that can help you out!!!!! if no on this problem but maybe one later on!!
2006-09-04 22:03:09 · answer #3 · answered by Adam D. 6 · 0⤊ 0⤋