A. How far will a freely falling object fall from rest in five seconds? six second??
i got for 5 sec 25 meters, and for 6 sec 30 meters. Is this right? If not please explain.
B. How far will an object move in one second if its average speed is 5m/s? Is it 5 meters??? i could be wrong
thanks for help!
2006-09-04 13:30:52 · 4 answers · asked by ♥ 3 in Science & Mathematics ➔ Physics
A.
I assume that you mean under the influence of the earth's gravity. That acceleration is a= 9.8 m/s/s. Integrate this twice to get:
d = a*t^2/2 , that is , one-half acceleration multiplied by time squared. For t=5 sec this becomes 9.8 * 25/2 = 122.5 meters. For 6 sec d = 176.4 meters.
B.
With no unbalanced forces on the object it will just move at that constant speed. So, yeah, it's 5 m/s multiplied by 1 sec = 5 meters. However, perhaps what is meant is a modification of the part A problem. If instead of starting at rest the object is moving in the same direction (down) as gravity, then it's distance is
d = a*t^2 + v*t
where
a=gravity's acceleration= 9.8 m/s/s
v = 5 m/s
2006-09-04 13:45:33 · answer #1 · answered by modulo_function 7 · 0⤊ 0⤋
A. S =gt^2/2 g=10m/s^2
1. s =10 *25/2 =125 m
2 S = 10*36/2 = 180 m
B. 5 m
2006-09-04 13:41:49 · answer #2 · answered by eaismeg 3 · 1⤊ 0⤋
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2016-11-24 21:54:48 · answer #3 · answered by duggins 4 · 0⤊ 0⤋
i believe it is correct
2006-09-04 13:36:36 · answer #4 · answered by rlt101010 2 · 0⤊ 0⤋