Question about a Equation. (4/2+7/3+2=5/3+1)?

Question

Ok so if I wanted to get rid of the fractions I would multiply by 6, but does the fraction cancel out the 6?
Eg. Would my next line be: 24+42+12= 30+6 or 4+7+12= 5+6 ?
I think it's the 1st one but I need to know for sure for a test coming up.

This is not an actual problem I just wanted to see what to do as 1st step

Ok yea I did mess up the start I think the next line would be.
12+14+12=10+6
38=16 -which yes is not a true equation.

Answer 1

4/2+7/3+2=5/3+1

Here's what's up:

2+7/3+2=5/3+1 (4/2 reduces to 2)
3*(2+7/3+2=5/3+1) (multiply through by 3 to eliminate the need for the denominators:)
6 + 7 + 6 ?= 5 + 3
19 <> 8

As you can see, this isn't an equation since the left side is far greater than the right.

Answer 2

If you did it all by 6, it would be 6(4/2 + 7/3+2 = 5/3+1)
24/2+42/3+12=30/3+6
12+14+12=10+6
38=16 untrue

Answer 3

Whoa, hold on.
If you multiply by 6:
24/2+42/3+12=30/3+6
12+14+12=10+6
38 does not equal 16
Is there something missing here?

Answer 4

dude, you multiply each number by 6, which leaves you with 24/2 (12) + 42/3 (14) +12 = 30/3 (10) +6

the problem i have is... what's the rest of the equation? because 38 does not equal 16

Answer 5

24/2+42/3+12=30/3+6
12+14+12=10+6
38=16 ????
I think you copied the problem incorrectly!

Answer 6

No, you would do 4/2 =12/6 (multiply each by 3 to get denominator as 6) and then multiply by 6, canceling out the denominator, getting 12. So you make all the denominators 6 then multiply all by 6, canceling denominator, getting nominator. Does that make sense?