1,1,2,3,5,8,13
Fibonacci series--The next number is the sum of the two pervious numbers.
1,1,2,3,3,4,5,5,6,7,7,8,9,9..
odd numbers appear twice, even numbers once, and then number increases by 1
1,1,2,3,4,4,5,6,6,7,8,8,9,9,10,10,11,12,12..
prime numbers appear twice, non-prime numbers once, and then number increases by 1
1,1,2,3,4,4,5,6,7,8,9,9,10,11,12,
perfect squares appear twice, non-perfect squares appear once
1,1,2,3,4,4,4,5,6,7,8,9,9,9,9,9,9,9,9,9,9,10,11,12
let the perfect square =x^2
the perfect squares appear x^2+1 times, non-perfect square appear once
1,1,2,3,4,4,4,5,6,7,8,9,9,9,9,10,11,12
let the perfect square =x^2
the perfect squares appear x+1 times, non-perfect square appear once
2006-09-04 19:12:07
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answer #1
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answered by PC_Load_Letter 4
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1, 1, 2, 3, 5, 8, 13 (x_n = x_(n-1) + x_(n-2); x_0=1, x_1=1 - this is also known as the fibonacci sequence)
1, 1, 2, 3, 3, 1, -4 (x_n = -1/6 n³ + n² - 5/6 n + 1 - this is the unique third-degree polynomial that passes through all of the first four points)
1, 1, 2, 3, 8, 15, 48 (x_n = n!/x_(n-1); x_0=1 - this one I just made up).
2006-09-04 12:14:12
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answer #2
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answered by Pascal 7
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I got three:
1,1,2,3,5,8,13 - Fibonacci
1,1,2,3,1,4,5 - the integers with an extra 1 every 4th digit
1,1,2,3,3,2,1,1 - symmetrical
2006-09-04 12:00:18
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answer #4
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answered by tiggeronvrb 3
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1,1,2,3 2,2,3,4
1,1,2,3 4,4,5,6
1,1,2,3 4,5,6,7
2006-09-04 12:03:02
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answer #7
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answered by zahbudar 6
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