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If you had one positive charge +q1 and one negative charge -q2 and suppose we place a third charge along the line between the two charges. Zone 1 is left of the positive charge. Zone 2 is between the positive charge and the negative charge. Zone 3 is right of the negative charge. This third charge can be in equilibrium if the electric force from the positive can balance the electric force from the negative charge. Than how would you consider the following statements??

True or False -- A negative charge placed in Zone 2 can be in equilibrium.

True or False -- A negative charge placed in Zone 1 can be in equilibrium.

True or False -- A positive charge placed in Zone 2 can be in equilibrium.

True or False -- A positive charge placed in Zone 3 can be in equilibrium.

True or False -- A negative charge placed in Zone 3 can be in equilibrium.

True False A positive charge placed in Zone 1 can be in equilib

2006-09-04 10:49:20 · 2 answers · asked by eltel2910 1 in Science & Mathematics Physics

2 answers

First observe that a charged particle can only be in equilibrium if the electrostatic fields from q1 and -q2 cancel each other at the position of the third charge.
Therefore the charge (positive or negative) of the third particle is not relevant.

The two electrostatic fields cannot cancel each other in zone two because the field-lines have the same direction in this region.
In zones 1 and 3 there can be places where the resulting field is zero because the two fields have opposite direction in these regions.

=> Answers with zone 2 are false
Answers with zone 1 or 3 are true

2006-09-04 11:24:12 · answer #1 · answered by mitch_online_nl 3 · 0 0

I believe that whosever made up this test had no idea what a charge is and what their interaction is.
plus or minus can indicate addition or substraction ,and also indicate direction of motion and neutral means no motion or is to big to interact with something smaller.Alot of confusion about (+ or - or =not + or not -)

2006-09-04 11:11:10 · answer #2 · answered by goring 6 · 0 0

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