2006-09-04 09:03:31 · 5 answers · asked by christine2550@sbcglobal.net 2 in Science & Mathematics ➔ Earth Sciences & Geology
If it was at a vapor near atmospheric pressure when you started, it would go to about to about 60 psig.
If it was a liquid when you started, then it would go to many thousands of psi.
Note that mild steel is not sufficient to go to 1500 F. But if you are using something better at high temps:
There would a shift in the chemical species present. Even at 920-970F (with platinum catalyst), reactions would happen. At 1500F, you wouldn't need the catalyst.
The fraction of the straight chain species (hexane, septane, octane, nonane) would form aromatic (ring) structures like cyclohexane, benzene, toluene, xylenes, etc.
This is desirable because those more centralized molecules have higher octane ratings. The downside, discovered since the widespread use of "reforming" reactors in the 1970s, is that those compounds are carcinogenic.
Those reactions are endothermic - they absorb heat.
In a practical reforming scheme, you have a recirculating loop that separates out the desired fractions and sends the rest back to the reformer while controlling the hydrogen concentrations. You get 5-10% conversion in each pass.
2006-09-05 11:52:28 · answer #1 · answered by David in Kenai 6 · 0⤊ 0⤋
Assuming your container can withstand the heat and pressure, it would form a superheated mass of gasoline vapor.
2006-09-04 16:08:53 · answer #2 · answered by juicy_wishun 6 · 0⤊ 0⤋
presuming the container did not explode, nothing.....
2006-09-04 16:11:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
you dont wanna be close enough to find out.believe that.
2006-09-04 16:09:14 · answer #4 · answered by goodstuff28602 2 · 0⤊ 0⤋
Try it and then let us know.
2006-09-04 16:12:42 · answer #5 · answered by smith6969_99 2 · 0⤊ 0⤋