A diamond ring with 0.23 carats diamond in gucci store price is about 2000 us. but same type ring in other store the price is more lower.why??is it jist about the Gucci brand so price is high.Or about the diamond??
2006-09-04 07:50:36 · 10 answers · asked by qing 1 in Beauty & Style ➔ Fashion & Accessories
Its the brand name you are getting, not the diamond.
2006-09-04 07:52:52 · answer #1 · answered by shell7024 3 · 0⤊ 0⤋
1.) A Gucci ring is NOT higher then all others.
2.) The reason for it's higher price is cause it IS a GUCCI.
3.) No one will KNOW it's a GUCCI other then yourself, so no point in buying it.
4.) Cartier is probably your #1 seller of diamonds.
5.) .23 carats? My that's awfully small...
2006-09-04 15:02:10 · answer #2 · answered by ICG 5 · 0⤊ 0⤋
the diamond you saw @ the gucci store could have had a much higher rating and any time you buy a brand name you r paying for the name say you had two of the exact same quality diamond rings one is from gucci and the other is from target I think when you were asked where you got it you would rather say gucci. hence paying for the name.
2006-09-04 14:57:12 · answer #3 · answered by krazy salazar 2 · 0⤊ 0⤋
Hello it Gucci!
2006-09-04 15:18:08 · answer #4 · answered by love me like me hate me 5 · 0⤊ 0⤋
its a big brand, advertising expenses adds to the cost of actual ring, u can get a better deal with less familiar brand.
2006-09-05 03:27:23 · answer #5 · answered by tina-The lover 1 · 0⤊ 0⤋
its the gucci brand
2006-09-07 11:40:41 · answer #6 · answered by jellybeans 3 · 0⤊ 0⤋
Same thing as a Harley Davidson. They're crappy bikes, but you pay out the *** for the name.
2006-09-04 14:56:14 · answer #7 · answered by dirtmerchant_12b 3 · 0⤊ 0⤋
Name brands are ALWAYS higher than more unknown brands - go figure!@
2006-09-04 14:53:07 · answer #8 · answered by nswblue 6 · 0⤊ 0⤋
The name has to be the reason, why else?
2006-09-04 19:37:07 · answer #9 · answered by native_american_chick 2 · 0⤊ 0⤋
ITS GUICCI DUH
2006-09-04 14:59:49 · answer #10 · answered by #1 tweety fan 2 · 0⤊ 0⤋