hi u all,what we mean by beautiful.It is good to be more beautiful.
2006-09-04 07:07:30 · 23 answers · asked by little m 1 in Beauty & Style ➔ Other - Beauty & Style
preity zinta rocks......
2006-09-04 07:10:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I think Rani looks more attractive as a mature woman while Preity appears more cute as an adorable teenager ...
2006-09-05 19:39:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i use to like preity more than rani, but i like rani now.
because zinta is looking not so good now-a-days, and rani is winning heart by her roles and attitude. where as zinta is doing all similar roles and loosing her charm!!!!!
2006-09-04 18:16:08 · answer #3 · answered by Arif 4 · 0⤊ 0⤋
Beauty wise it is Rani. But Preity has such lovely dimples.
2006-09-06 18:55:04 · answer #4 · answered by Anonymous · 0⤊ 0⤋
For me Preity zinta .She looks bubbly,attractive and refreshing.Rani looks mature and no doubt her eyes are very beautiful
2006-09-07 20:03:27 · answer #5 · answered by riya k 2 · 0⤊ 0⤋
Preeti Zinta She Is My Sister Right Preeti
2006-09-05 21:48:03 · answer #6 · answered by accent_raman 1 · 0⤊ 0⤋
internally rani mukherji is much more beautiful than preity zinta but when you see externally preity zinta is much more beautiful.
2006-09-04 07:39:05 · answer #7 · answered by ken_yur 1 · 0⤊ 0⤋
if u wud have requested this question a twelve months in the past, it wud be rani for particular. yet now preity is gaining weight swifter and swifter. did not u see her on KBC with rani? she appeared lots fatter
2016-12-14 18:02:09 · answer #8 · answered by ? 3 · 0⤊ 0⤋
preity zinta is slightly better.i saw her photo in google
everyone has different opinions about it.
2006-09-07 22:43:55 · answer #9 · answered by Anonymous · 0⤊ 0⤋
for one it may be preity for another rani....overall both are good looking .........and talented else they would have been out of the film industry
2006-09-04 07:16:57 · answer #10 · answered by othikata 2 · 0⤊ 0⤋
Rani!
2006-09-07 23:28:43 · answer #11 · answered by Anonymous · 0⤊ 0⤋