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Sphere has the highest volume to surface area ratio. Which solid shapes have the least volume to surface area?

2006-09-04 07:05:07 · 17 answers · asked by Anonymous in Science & Mathematics Mathematics

By solids I meant regular 3-D geometrical shapes like cube etc..

2006-09-04 08:23:45 · update #1

17 answers

An extremely thin plane, like a piece of paper maybe?

For example if you had an object that measured 10'x10'x0.01' its total volume would be 1 cubic foot, but its surface area would be
2(10x10) + 4(10x0.01) = 200.4 square feet.

That would give you a ratio of 200.4 feet.

0.01 feet is pretty thick. If we made it 1% as thick, that would give us a ratio of 20,000.004 feet. You see where I'm going with this.

2006-09-04 07:07:56 · answer #1 · answered by Anonymous · 1 0

That would be the heaviest solids if weight and shape were the identity characteristics. Take 2 objects of identical weight and shape. The densest one, such as plutonium would have least volume. Quite recently
2 new elements have been discovered at Berkeley -
116 and 118 (identified by their number of protons).
But if you are looking for a shapewise answer then it
would be a flat sheet. The flatter, the better to fulfill your
requirement to minimize volume to surface. And I claim
it would not matter what 2 dimensional shape it took so long as it was flat. As a thought experiment, imagine that
an object could be flattened down to 1 molecule thick.
You would have all molecules exposed and the area would
be the area of 1 molecule times the number of molecules
in the object. So the 2 dimensional shape would not matter. Flatness is the key.

2006-09-04 07:23:24 · answer #2 · answered by albert 5 · 0 0

I am not quite sure about which particular regular geometrical shape will it be...but definitely a hollow cube is going to have a much larger Surface are(S.A) than a closed one...similarly a hollow cone can have much larger S.A than an enclosed one ...or for that matter even a cuboid...there are so many regular geometrical petterns you can think of...regular tetrahedron,octagedron,hexagonal....and so on...but to find out which has a least S.A would require a comparative study of all the figures having same volume,express their volumes in terms of area and then equate their derivatives to zero and follow the method of maxima/minima...to determine the least of all...firstly this method is too cumbersome...and next...there is no end to the set of regular geometrical patterns that a sold might have....mathematicians and scientists are still cracking their brains over the search of more regular geometric structures..that a solid might assume.....

2006-09-11 02:56:38 · answer #3 · answered by geek24 1 · 0 0

Well now lets see what the question really is lol? If you are talking surface area like a 6" dia sphere, a 6"x 6" x 6" cube, or a 6" x 6"x 6" equal lateral triangle. The the Triangle would be the least surface area.

2006-09-12 03:46:34 · answer #4 · answered by jjnsao 5 · 0 0

Maximize surface area by increasing the amount of lumps!

Star shaped solids have more surface area to volume.

If you developed a solid with a fractal surface, you could have infinite surface area in a finite volume! Look at the geometric shapes in the mathworld wolfram site and see how the circumference can increase but the enclosed area would reach an outer limit. Apply this 3 dimensionally!

And I like K Biz's answer as well...

two dimensional (or as close as possible to it) object will have very high surface area to volume

but I like my infinite surface area better :)

2006-09-04 07:16:41 · answer #5 · answered by Orinoco 7 · 0 0

According to the chaos theorem, the fractals shows that it is possible to get a solid with an infinitely large surface area and finite volume. this is not a definite solid it is a general case. According to this fact the requires ratio will be a zero

2006-09-11 02:28:24 · answer #6 · answered by Hassan g 2 · 0 0

mmm. as of yet, mathematically impossible question. You can imagine a plane as having that, or as others suggest, some 3D object with highly folded ridges along the surface...

However, it is impossible to define because you can always have a thinner rectangular plane stretching out farther and farther to infinity, or add one more ridge, etc.

However, if you find an equation that will give us a conclusion other than infiniti, I'm pretty sure you'll get a Nobel Prize in Mathematics for that. :)

So yah, the answer is that it does not exist (or infinit, whatever).

2006-09-11 05:31:15 · answer #7 · answered by jarizza 2 · 0 0

I think it'd be solid shapes with numberous hollow cut throughout the object. One example of a light object which gives you maximized surface area is the lung.

2006-09-12 00:47:06 · answer #8 · answered by Papoo 1 · 0 0

volume could only be determine if dimensions are given from any object of your choice. Only then you could answer your question.
Sample: a ring box 1/2" x 1/2" x 1/2 will have less volume than the Louisiana Superdome.

2006-09-11 13:22:17 · answer #9 · answered by Liwayway 3 · 0 0

This is the type of question you might have in a differential geometry class. However, the way you stated it makes me think that there is no solution. For a typical minimal surface problem you would have some sort of boundary condition.

2006-09-12 02:18:23 · answer #10 · answered by bruinfan 7 · 0 0

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